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The additivity of the classical capacity of any memoryless
quantum channel remains an open problem in quantum information theory.
The Holevo-Schumacher-Westmoreland (HSW) theorem states that the
classical capacity of a memoryless quantum channel Λ utilizing product state encoding
is given by the formula,
χ = max{pi, ρi}S(∑ipiΛ(ρi)) − ∑ipiS(Λ(ρi))
for S(ω) the von
Neumann entropy of the state ω.
Product state encoding is a form of block coding that takes n copies of a channel Λ⊗n and encodes
the input message into a product state codeword m → ρi1 ⊗ ρi2 ⊗ ... ⊗ ρin.
The output from the block encoding is thus also a product state Λ(ρi1) ⊗ Λ(ρi2) ⊗ ... ⊗ Λ(ρin).
However, there is nothing stopping the sender encoding the message into
states that are entangled across channels such that the input
ρ(n)i
and possibly the output (Λ ⊗ Λ ⊗ ... ⊗ Λ)(ρ(n)i)
are entangled. The HSW theorem states that the capacity for input states
that are product states for blocks of channels of size n, is thus,
$$\chi_n = \max_{ \{ p^{(n)}_i,
\rho_{(n)}^i \} } \frac{1}{n} \Big[ S\Big( \sum_i p^{(n)}_i
\Lambda^{\otimes n}(\rho_{(n)}^i) \Big) - \sum_i p^{(n)}_i
S\big(\Lambda^{\otimes n}(\rho_{(n)}^i)\big) \Big]$$
where the ensemble of states {pi(n), ρ(n)i}
may be entangled across blocks of n channels.
Asymptotically, this leads to the expression for the classical
capacity in regularized form,
$$C(\Lambda) = \lim_{n \rightarrow \infty}
\max_{ \{ p^{(n)}_i, \rho_{(n)}^i \} } \frac{1}{n} \Big[ S\Big( \sum_i
p^{(n)}_i \Lambda^{\otimes n}(\rho_{(n)}^i) \Big) - \sum_i p^{(n)}_i
S\big(\Lambda^{\otimes n}(\rho_{(n)}^i)\big) \Big]$$
It is straightforward to see that C(Λ) ≥ χ. The
additivity problem is then to prove (or disprove) the
conjecture that C(Λ) = χ, giving a
"single-letter" formula for the classical capacity of a memoryless
quantum channel.
Category:Quantum
Communication
Last modified:
Monday, October 26, 2015 - 17:56